9x^2-4/3x^2-5x+2

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Solution for 9x^2-4/3x^2-5x+2 equation: 


x in (-oo:+oo)

9*x^2-((4/3)*x^2)-(5*x)+2 = 0

9*x^2+(-4/3)*x^2-5*x+2 = 0

23/3*x^2-5*x+2 = 0

DELTA = (-5)^2-(2*4*23/3)

DELTA = -109/3

DELTA < 0

x belongs to the empty set

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